Today, I accomplished something even my Honors Algebra teacher couldn’t.
I graphed Batman on my trusty TI-83, Bessie.
It took me literally 45 minutes to get it right. I used three different equations before I got the desired result. If you want to give it a try:
Equation #1 (failure):
Y1 = 1.5sqrt(-abs(abs(x)-1)*abs(3-abs(x))/((a¬bs(x)-1)*(3-abs(x))))(1+abs(abs(x)-3)/(a¬bs(x)-3))sqrt(1-(x/7)^2)+(4.5+0.75(abs(x¬-.5)+abs(x+.5))-2.75(abs(x-.75)+abs(x+.7¬5)))(1+abs(1-abs(x))/(1-abs(x)))
Y2 = -3sqrt(¬1-(x/7)^2)sqrt(abs(abs(x)-4)/(abs(x)-4))
Y3 = abs(x/2)-0.0913722(x^2)-3+sqrt(1-(abs(a¬bs(x)-2)-1)^2)
Y4 = (2.71052+(1.5-.5abs(x))-1¬.35526sqrt(4-(abs(x)-1)^2))sqrt(abs(abs(¬x)-1)/(abs(x)-1))
Yeah… there are some cowboys in that one. Number two is a bit better.
Equation #2:
I like this one because it’s colorful. The different colors are different Y=’s. Go for it!
Equation #3:
Number three require you to change to “PAR” in mode. These are the parameters:
X1 = {1, -1}(2.5sin(.5T) + 4)
Y1 = .7T + 2
X2 = {1, -1}(7sin(.5T) + 4)
Y2 = 1.8T – 1.5π
X3 = {1, -1}(cos(.5T) + 1)
Y3 = 2sin(.5T) – .1T2 – 3
X4 = {1, -1}(.25T + 2)
Y4 = .5T-1 + 2
X5 = .6T – .6π
Y5 = .75sin(.5T) + 5
X6 = {1, -1}(1.4cos(.6T) – 3.4)
Y6 = 1.7sin(.6T) – 3
And that was the successful one!
I think because I did this, I shouldn’t have to to my homework tonight… eh?
Algebra’s your friend, mate!
Love,
The Calculator Gotham Deserves
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